Simple Ajax Call

var form = $('#main-contact-form');

 form.submit(function(event){

  event.preventDefault();

  var form_status = $('<div class="form_status"></div>');

  $.ajax({

   url: $(this).attr('action'),
   method : 'POST',
   data : $(this).serialize(),
   beforeSend: function(){

    form.prepend( form_status.html('<p><i class="fa fa-spinner fa-spin"></i> Email is sending...</p>').fadeIn() );

   }

  }).done(function(data){

   form_status.html('<p class="text-success">Thank you for contact us. As early as possible  we will contact you</p>').delay(3000).fadeOut();
   $(this).reset();
  });

 });